Converting a series of data with the following format JD:HH:MM:SS:SSSSSS to Julian day.Fractional secs of the day in python

Question

I have some time data that I need to modify in order to convert it into Julian day. fractional seconds of the day (i.e. 270.79514 = 9 Sep 2022 7:05). The format for the time I am converting is Julian day:hh:mm:ss:ffff(microseconds) and I need this in UTC time or I need to remove the Julian day piece to do the conversion. All in python.

time = 234:16:54:01:695230

output I am looking for = 234.62085295

Is there a method using datetime function to make the change or do I have to remove the Julian day portion first before I can use the time piece to get the fractional seconds of the day?

Answer 1

I don't understand you very well but maybe this can help you.

date = '234:16:54:01:695230'
days,hours,minutes,seconds,micsec = map(lambda x:int(x),date.split(':'))
fractional = days+(hours+(minutes+(seconds+(micsec/1000000))/60)/60)/24