I'm modernizing some old Fortran code and I cannot get rid of an equivalence statement somewhere (long story short: it's mixed use is so convoluted it'd take too much work to convert everything).
I need the length of the EQUIVALENCEd arrays to depend on some input, like the following code:
program test_equivalence
implicit none
type :: t1
integer :: len = 10
end type t1
type(t1) :: o1
call eqv_int(o1%len)
call eqv(o1)
return
contains
subroutine eqv_int(len)
integer, intent(in) :: len
integer :: iwork(len*2)
real(8) :: rwork(len)
equivalence(iwork,rwork)
print *, 'LEN = ',len
print *, 'SIZE(IWORK) = ',size(iwork)
print *, 'SIZE(RWORK) = ',size(rwork)
end subroutine eqv_int
subroutine eqv(o1)
type(t1), intent(in) :: o1
integer :: iwork(o1%len*2)
real(8) :: rwork(o1%len)
equivalence(iwork,rwork)
print *, 'LEN = ',o1%len
print *, 'SIZE(IWORK) = ',size(iwork)
print *, 'SIZE(RWORK) = ',size(rwork)
end subroutine eqv
end program test_equivalence
This program will create 0-length arrays with gfortran 9.2.0. This is the output:
LEN = 10
SIZE(IWORK) = 0
SIZE(RWORK) = 0
LEN = 10
SIZE(IWORK) = 0
SIZE(RWORK) = 0
The same code will return Array 'rwork' at (1) with non-constant bounds cannot be an EQUIVALENCE object when compiled with gfortran 5.3.0, the warning disappears since gfortran 6.2.0, but the size of the arrays is always 0. So maybe compiler bug?
The source code is indeed not a valid Fortran program. To be specific, it violates the numbered constraint C8106 of Fortran 2018:
Being a numbered constraint, the compiler must be capable of detecting this violation. If hasn't such a capability this is a deficiency in the compiler (a bug). Being "capable" doesn't mean doing so by default, so please look carefully to see whether there are options which do lead to this detection. Someone familiar with the internals of GCC can give further detail here.
As the source isn't a valid Fortran program, the compiler is allowed to consider the arrays of size zero if it has skipped the violation detection.