This is a minimized part of Pointer to implementation code:
template<typename T>
class PImpl {
private:
T* m;
public:
template<typename A1>
PImpl(A1& a1) : m(new T(a1)) {
}
};
struct A{
struct AImpl;
PImpl<AImpl> me;
A();
};
struct A::AImpl{
const A* ppub;
AImpl(const A* ppub)
:ppub(ppub){}
};
A::A():me(this){}
A a;
int main (int, char**){
return 0;
}
It compilable on G++4.8 and prior and works as well. But G++4.9.2 compiler raise following errors:
prog.cpp: In constructor 'A::A()':
prog.cpp:24:15: error: no matching function for call to 'PImpl<A::AImpl>::PImpl(A*)'
A::A():me(this){}
^
prog.cpp:24:15: note: candidates are:
prog.cpp:9:5: note: PImpl<T>::PImpl(A1&) [with A1 = A*; T = A::AImpl]
> PImpl(A1& a1) : m(new T(a1)) {
^
prog.cpp:9:5: note: no known conversion for argument 1 from 'A*' to 'A*&'
prog.cpp:2:7: note: PImpl<A::AImpl>::PImpl(const PImpl<A::AImpl>&)
class PImpl {
^
prog.cpp:2:7: note: no known conversion for argument 1 from 'A*' to 'const PImpl<A::AImpl>&'
But it can be fixed by small hack. If i pass '&*this' instead of 'this' then it bring to compilable state.
Is it G++ regression or new C++ standards feature which eliminate backward compatibility?
This didn't compile for me with gcc-4.6, so it seems that gcc-4.8 is where the regression occurred. It seems what you want is to take
A1
by universal reference, ie:PImpl(A1 && a1)
. This compiles for me with both gcc-4.6, gcc-4.8 and gcc-4.9.