How can I create multiple children using one parent with 2D array for UNIX using pipes and fork only?

Question

I'm trying to write code that creates N processes 1, 2, 3, 4, ..., N for UNIX (using fork()), where N is given by the user. The processes can be created in any order. Each process must print indefinitely the order in which was created, its process id, as well as its serial number message it prints. Process messages must be printed alternately, in order in which the processes were created. Only using pipes() and fork() .The program will terminates when the user types Ctrl-C

How can I synchronize my processes properly?

**Here is my code : **

#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
#include <string.h>

int main()
{
    int pd[2]; 
    int p; 
    int i; 
    int N;
    int x=0;       
     
    printf("Give me the number of the processes: ");
    scanf("%d", &N);
    for(i=0; i<=N; i++)
        p=fork();
    if (p==0)
    {      
        close(pd[1]);        
        for(i=0; i<N; i++)
        {
            pipe(pd);
            printf("Proccess child %d has Process id_ %d ,message %d\n", i,getpid(),x+1);
            sleep(1); 
            write (pd[1], &x ,sizeof(x));
            read (pd[0] , &x ,sizeof(x)) ; 
            x++;
        }
    }
    else 
    {
        close(pd[0]);
        for(i=0; i<N-1; i++)
            sleep(1); 
    }
    
    return(0);
}

This is my terminal:

terminaloutput

How can I create multiple processes and print them out like that ex. if Ν=3, terminal output:

Process 1 has process id_1, message 1
Process 2 has process id_2, message 1
Process 3 has process id_3, message 1
Process 1 has process id_1, message 2
Process 2 has process id_2, message 2
Process 3 has process id_3, message 2
Process 1 has process id_1, message 3
Process 2 has process id_2, message 3
Process 3 has process id_3, message 3