How can ı define a char taking from digit of a number in Java?

Question

Scanner s = new Scanner(System.in);
        String num = s.next();

        char a = num.charAt(0);
        char b = num.charAt(1);
        char c = num.charAt(2);
        char d = num.charAt(3);

For example , we can do it like this but i will enter long values ​​for input so how can i write it like loop or easier rather than write 20 line as ı wrote ?

I thought , i can write it using "for" but i couldn't.I am new to java so if you can solve it using basic methods or codes and explain so , i would be grateful.

Scanner inp = new Scanner(System.in);
    System.out.println("Enter the number");
    String num = inp.next();

    char a = num.charAt(0);
    char b = num.charAt(1);
    char c = num.charAt(2);
    char d = num.charAt(3);
    char e = num.charAt(4);
    char f = num.charAt(5);
    char g = num.charAt(6);
    char h = num.charAt(7);

    if (a < '2') {
        System.out.print("0" + "" + b + "" + c + "" + d + "" + e + "" + f + "" + g + "" + h);
    } else if (a > '2' & h == '0') {
        System.out.print("0" + "" + b + "" + c + "" + d + "" + e + "" + f + "" + g + "" + "1");
    } else if (a > '2' && h == '1') {
        System.out.print("0" + "" + b + "" + c + "" + d + "" + e + "" + f + "" + g + "" + "0");
    }

As well,Im trying for easier way of that.

Thanks in advance.

Answer 1

You can't do this with variables named a, b, c, etc. You could only do it with an array, where you could index them by number, e.g. char[] chars, and use chars[0] instead of a, chars[25] instead of z, and so on.

To do that, you can just do char[] chars = num.toCharArray(), or even skip the array entirely and keep using charAt.