How to enable IntelliSense and indexer at the same time in typescript?

Question

For example, I have an object:

const obj = {
  a: (valueA: string) => true;
  b: (valueB: string) => false;
  c: (valueC: string) => false;
};

You see all properties in this object have same type ((value: string) => boolean). Now I want it to have IntelliSense which makes follows possible:

1. Display a, b, c after I typed obj.;
2. Limit its type when I try to add a property into obj.

I tried indexer:

const obj: Record<string, ((value: string) => boolean)> = {
  a: (valueA: string) => true;
  b: (valueB: string) => false;
  c: (valueC: string) => false;
};

But now target 1 won't happen, if I don't use indexer, I cannot achieve target 2.

Answer 1

Variable inference is either all or nothing, you either let typescript infer the type or you specify the type yourself.

You can only do this with a helper function:

function makeFunctionsMap<T extends Record<string, ((value: string) => boolean)>>(o: T) { return o; }
const obj = makeFunctionsMap({
  a: (valueA: string) => true,
  b: (valueB: string) => false,
  c: (valueC: string) => false,
})
obj.a;
obj.d // Error

Playground Link

You can also inline the function if you want to make it shorter and more unreadable (Playground Link)