How to Fix Error 1053 : The service did not respond to the start or control request in a timely fashion?

Question

I created a very simple 2-line Python program, then I made it into an executable file :

print("Hello World!")
input("Press a key to exit.")

Then I created a windows service called 'hello' linked to this .exe file. The problem is that, when I try to start the service, it starts, but halfway through loading, this error appears 'Error 1053 : The service did not respond to the start or control request in a timely fashion'.

I've already tried this on regedit with the 180000, but it didn't work. Apparently the problem comes from a debug mode, but I don't understand it at all.

Thank you ;)

Answer 1

I think that when Windows starts the service it escpect a return code of success of failure. Since you have input() as your last line of code the python process is waiting for user input, thus not finalizing and not sending any return code.