Interface Builder show all @IBInspectable in cascade

Question

I'm maybe too complicated, but here is what I want:

@IBDesignable
class A: UIView {
    @IBInspectable var title: String = "" {
        didSet {
            setNeedsLayout()
        }
    }
}

@IBDesignable
class B: UIView {
    var firstView: A = A()
    var secondView: A = A()
}

The B class have 2 @IBDesignable classes, so if I want to customize B directly in Interface Builder, I can't as I don't have access to the 2 A classes.

At first I create a protocol to list all elements in A class, but when a view need 2 or more item of A class, I can't use this.

Do someone have an idea to have only 1 B class in my storyboard and can customize both A classes?

Answer 1

Not very sure if your this is possible. This is not usually possible even when you use Apple Library classes, for example a UIButton has a UIView and also a UILabel.

Though these different classes and some things are possible by overriding as explained here

But I can provide you a hack here. In the object that you create for Object B in storyboard, you can add User Defined Runtime Attributes as follows -

firstView.title & secondView.title

I know this might not be the answer you are looking for, but thats just a way around.