PHP What browser the user is using?

Question

PHP What browser the user is using?

112 Views Asked by user2498092 At 16 November 2025 at 05:23

This is my current code, but I get a parse error when I run it? Have I just made a silly error or will this not work? Thanks in advance.

<html>
<head>
<title>PHP Test</title>
</head>
<body>
<?php 
browser();
function browser() {
    $browsers = array('chrome', 'msie', 'firefox', 'safari');
    for ($i = 0; $i < $browsers.length + 1; $i++) {
        if (SERVER['HTTP_USER_AGENT'] == $browsers[$i]) {
            echo "You are using {$browsers[$i]}.";
        }
    }
}
?>
</body>
</html>

Original Q&A

There are 1 best solutions below

**Giacomo1968** · Answer 1

There are a couple of issues with your code. First $browsers.length is not the way that value is calculated in PHP. It seems like .length is a JavaScript format? It should be count($browsers). Also, you have SERVER['HTTP_USER_AGENT'] when it should be $_SERVER['HTTP_USER_AGENT']. I also changed your echo format so it’s more readable. This should work without failing completely:

browser();
function browser() {
    $browsers = array('chrome', 'msie', 'firefox', 'safari');
    for ($i = 0; $i < count($browsers) + 1; $i++) {
        if ($_SERVER['HTTP_USER_AGENT'] == $browsers[$i]) {
            echo "You are using " . $browsers[$i] . ".";
        }
    }
}

But if I were you I would approach your logic as so using in_array instead of a for loop:

browser();
function browser() {
    $browsers = array('chrome', 'msie', 'firefox', 'safari');
    if (in_array($_SERVER['HTTP_USER_AGENT'], $browsers) {
        echo "You are using " . $_SERVER['HTTP_USER_AGENT'] . ".";
    }
}

Basically that for loop is excessive for the logic presented. Just use in_array to check of the value of $_SERVER['HTTP_USER_AGENT'] is actually in $browsers.

That said, browser detection is not as simple as your overall logic implies. But this at least solves your most immediate PHP problems at gives you something to build on.

PHP What browser the user is using?

There are 1 best solutions below

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