In my Play scala project I have multiple selection of drop down items.I have viewed my scala.html file successfully with multiple selection of values in drop down.
What I need
When submitting a form I need to pass multiple selected drop down values(List[Int]) from form to controller for this I have used employeeForm("languagesids").value but It shows below error
[error] found : Option[String]
[error] required: List[Int]
I have tried with employeeForm("languagesids").get but this too couldn't help.
and also its showing
No URL path bind
er found for type List[Int]
this error in routes file
What I tried
I tried with accessing a selected value list in Controller by below code
def registerEmployee = Action { implicit request =>
algorithmForm.bindFromRequest.fold(
formWithErrors => BadRequest(html.employeeRegisterForm(formWithErrors,LanguageType.options)),
employee=> {
play.api.Logger.info("employee langauge list size :"+employee.languagesids.size)
It gives list size as 0 if we select items
controller/Employees.scala
val employeeForm= Form(
mapping(
"employeeid" -> ignored(None:Option[Int]),
"employeename" -> nonEmptyText,
"languagesids" -> ignored(None:Option[List[Int]])
)(models.Employee.apply)(models.Employee.unapply)
)
def createEmployee = Action { implicit request =>
Ok(html.employeeRegisterForm(employeeForm,LanguageType.options.options))
}
}
models/Employee.scala
case class Employee(
employeeid: Option[Int] = None,
employeename:String,
languagesids:Option[List[Int]] = None
)
case class LanguageType(
languageid: Option[Int] = None,
languagename: String
)
object Employee{
}
object LanguageType{
val simple = {
get[Option[Int]]("language_type.LANG_ID") ~
get[String]("language_type.LANG_NAME") map {
case languageid~languagename=> LanguageType(languageid,languagename)
}
}
def options: Seq[(String,String)] = DB.withConnection { implicit connection =>
SQL("select * from language_type")
foldLeft[Seq[(String, String)]](Nil) { (cs, c) =>
c.languageid.fold(cs) { id => cs :+ (id.toString -> c.languagename) }
}
}
}
views/employeeRegisterForm.scala.html
@(employeeForm: Form[Employee],languageTypes: Seq[(String, String)])
@form(routes.Employee.registerEmployee(employeeForm("languagesids").value) {
<fieldset>
@inputText((employeeForm("algoname"), '_label -> "Employee Name", '_help -> "",'placeholder -> "Employee Name")
@inputText(employeeForm("algodesc"), '_label -> "Employee Description", '_help -> "",'placeholder -> "Description")
@multiSelect(
employeeForm("languagesids"),
languageTypes,
'_label -> "Select Tags" ,'_default -> "-- Choose Tag --"
)
</fieldset>
<div class="actions">
<input type="submit" value="Create Employee" >
</div>
}
}
routes
GET /register/:languageList controllers.Employees.registerEmployee(languageList:List[Int])
views/multiSelect.scala.html
@**
* Generate an HTML multi-select.
*
* Example:
* {{{
* @select(field = myForm("categories"), options = options("A","B","C"))
* }}}
*
* @param field The form field.
* @param args Set of extra attributes.
* @param handler The field constructor.
*@
@import helper._
@(field: play.api.data.Field, options: Seq[(String,String)], args: (Symbol,Any)*)(implicit handler: FieldConstructor, lang: play.api.i18n.Lang)
@values = @{ field.indexes.map { v => field("[" + v + "]").value } }
@input(field, args:_*) { (id, name, value, htmlArgs) =>
<select id="@id" name="@name" @toHtmlArgs(htmlArgs) multiple="multiple">
@options.map { v =>
<option value="@v._1" @{if(values.contains(Some(v._1))) "selected" else ""}>@v._2</option>
}
</select>
}