For given α≥0, let x_α be the maximum solution of the equation:
(np.sqrt(R**2-x**2))/(R**R + α**R) = np.log(R*(math.e)**(-R)*x+1)
Solve the equation: Equation
I need a Python code for this. I don't know what means to find maximum x_α.
For given α≥0, let x_α be the maximum solution of the equation:
(np.sqrt(R**2-x**2))/(R**R + α**R) = np.log(R*(math.e)**(-R)*x+1)
Solve the equation: Equation
I need a Python code for this. I don't know what means to find maximum x_α.
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