I have some executor-classes that implements one or two interfaces (IHandleMessages<> and/or CommandExecutor<>).
Can I register all these executor classes - with whichever interface(s) it implements of the two - as services. Without ending up having all other interfaces on the class as services too.
My initial attempt was this:
public class Test
{
[Fact]
public void SomeTest()
{
var container = new WindsorContainer();
container.Register(Classes.FromThisAssembly().BasedOn(typeof(CommandExecutor<>)).WithService.Base().LifestyleTransient(),
Classes.FromThisAssembly().BasedOn(typeof(IHandleMessages<>)).WithService.Base().LifestyleTransient());
container.ResolveAll<CommandExecutor<object>>().Count().ShouldBe(2);
container.ResolveAll<IHandleMessages<object>>().Count().ShouldBe(2);
}
public interface IHandleMessages<T> { }
public interface CommandExecutor<T> { }
public class HandlesMessagesOnly : IHandleMessages<object> { }
public class HandlesMessagesAndExecutesCommands : CommandExecutor<object>, IHandleMessages<object> { }
public class ExecutesCommandsOnly : CommandExecutor<object> { }
}
But that does not work. Is there a solution for this?
I'm using Windsor 3.1.0.
EDIT: I guess what I'm really asking is: Is it possible to find the same type twice, and just have the discoverer add more services to that type's registration?
I've made a pull request to Windsor which was accepted in 3.2, and you can now do this:
Read more here