I'm attempting to use php to read the source of a separate php file. I'm attempting to use file_get_contents in the following manner
file_get_contents('http://www.example.com/someFile.php');
Unfortunately, the code above attempts to execute the php code rather than just reading the text as it would with any other file.
I came across an article which appears to address the issue, which led me to the following code:
file_get_contents('php://filter/convert.base64-encode/resource=http://www.example.com/someFile.php');
However this code has the same effect; It attempts to execute the php code.
How can I use php to read the source of another php file without attempting to execute the php in the file?
No, it doesn't.
What's happening here is that
file_get_contentsmakes a regular HTTP request forhttp://www.example.com/someFile.php, and the remote server at "example.com" is interpreting the PHP code. It serves the results up exactly as though you'd navigated tohttp://www.example.com/someFile.phpin your browser. Your script is downloading that output.file_get_contentsmost definitely does not execute the contents of the file after retrieving it. The only access your script has to "someFile.php" is what the remote server is willing to serve up;file_get_contentscannot somehow fetch the underlying PHP source any more than you could with your browser somehow view the PHP source.