Write a program to return the length of the longest word from a string whose length is even?

Question

Optional<Integer> opInt = Arrays.asList(s.split("\\s")).stream()
  .map(l -> l.length())
  .filter(l -> l % 2 == 0)
  .sorted(Comparator.reverseOrder())
  .findFirst();
System.out.println(opInt.get());

Have written code above for that. Can we write concise code for it.

Answer 1

1. Instead of using Arrays.asList().stream(), use Arrays.stream(…).

2. You can use method reference instead of using the lambda. l -> l.length().

3. You can replace .sorted(Comparator.reverseOrder()) with a .max()

4. Refactored Code:

  final OptionalInt max = Arrays.stream(s.split(" "))
      .mapToInt(String::length)
      .filter(l -> l % 2 == 0)
      .max();

  System.out.println(max.orElse(0));