I am running some SPARQL queries using the class ForwardChainingRDFSInferencer, which basic constructs an inferencer. For my examples I use the schema.org ontology.
My code looks like the following example
MemoryStore store = new MemoryStore();
ForwardChainingRDFSInferencer inferencer = new ForwardChainingRDFSInferencer(store); //the inference class
Repository repo = new SailRepository(inferencer);
repo.initialize();
URL data = new URL("file:/home/user/Documents/schemaorg-current-https.nt");
RDFFormat fileRDFFormat = RDFFormat.NTRIPLES;
RepositoryConnection con = repo.getConnection();
con.add(data, null, fileRDFFormat);
System.out.println("Repository loaded");
String queryString =
" PREFIX schema: <https://schema.org/>" +
" SELECT DISTINCT ?subclassName_one" +
" WHERE { " +
" ?type rdf:type rdfs:Class ." +
" ?type rdfs:subClassOf/rdfs:subClassOf? schema:Thing ." +
" ?type rdfs:label ?subclassName_one ." +
" }";
TupleQuery tupleQuery = con.prepareTupleQuery(QueryLanguage.SPARQL, queryString);
TupleQueryResult result = tupleQuery.evaluate();
while (result.hasNext()) {
BindingSet bindingSet = result.next();
System.out.println(bindingSet.toString());
stdout.println(bindingSet.toString());
}
repo.close()
What I want is to print two subclass levels down the class Thing. So if for example we have,
Thing > Action (sub-class 1) > ConsumeAction (sub-class 2) > DrinkAction
What I want is to return the class CosumeAction which is two levels (subclasses) down from class Thing, while using the inference java class.
The current query, as given in the code sample above, returns all the classes and subclasses from every class of the schema.org ontology. Thus, there is something that I do wrong while using the inference class.
You could remove the classes you are not interested in with
FILTER NOT EXISTS:Examples
For
DrinkAction(level 3):For
WearAction(level 4):