Am I wrong or this is right about pre-increment(++) operator

Question

ok if I type "++n" in c then the value of n is incremented by one but when i type this code the output is not as i expected

#include <stdio.h>
void main() {
    int n = 2;
    printf("%d %d\n", ++n, n*n);
    }

and then the output is 3 4 but when i ask this to chatGPT it shows the output is 3 9 even i asked it that "VS Code shows 3 4 and how " it says it might be issue with iDLe When i ask to it When i ask about the output i got in VS

When i type this code

#include <stdio.h>
void main() {
    int n = 2;
    printf("%d %d\n", ++n, n*n);
    }

i was expected to get "3 9" but i got "3 4" how

Answer 1

The current value of n is used consistently in the statement - i.e. it takes the value 2 for n in all three places and then it operates on it. For the first mention of n it increases its value by 1 and then uses the resulting value, but it has already (kind of in parallel) used the value of 2 for the second and third mentions of n.

Don't trust ChatGPT.

Answer 2

You cant access n in the same statement after ++

clangs warning:

main.c:4:21: warning: unsequenced modification and access to 'n' [-Wunsequenced]
  printf("%d %d\n", ++n, n * n);
                    ^    ~