Decimal to binary without for, while, or if loops

Question

How can I write a program that reads an integer and displays a binary number without using loops, just with binary operators? (Only with basic functions)

 #include<stdio.h>     
 #include<stdint.h>     
 #include<math.h>        
 int main()       
 {uint8_t a;      
 scanf("%hhd", &a);   
 //i have read the integer, but I don't know how to go on  
 return 0;      
 }      

Answer 1

Displays a binary number without using loops, just with binary operators:

#include<stdio.h>     
#include<stdint.h>     
#include<math.h>        
int main()       
{
  int a;      
  scanf("%u", &a);

  printf("Number: 0x%X\n", a);
  
  printf("%d", ((a & 0x80) >> 7));
  printf("%d", ((a & 0x40) >> 6));
  printf("%d", ((a & 0x20) >> 5));
  printf("%d", ((a & 0x10) >> 4));
  printf("%d", ((a & 0x08) >> 3));
  printf("%d", ((a & 0x04) >> 2));
  printf("%d", ((a & 0x02) >> 1));
  printf("%d", ((a & 0x01) >> 0));

  printf("\n");
  
  return 0;      
}      

Be careful, as the input is integer, I added a printf

131
Number: 0x83
10000011

Of course, it would be easier with loops :

int main()       
{
  int     a;
  uint8_t Mask;
  uint8_t Shift;
  scanf("%u", &a);

  printf("Number: %X\n", a);

  Mask  = 0x80;
  Shift = 7;
  
  while (Mask > 0)
  {
    printf("%d", ((a & Mask) >> Shift));
    Mask = Mask >> 1;
    Shift--;
  }

  printf("\n");
  
  return 0;      
}