How to capture second match from the given text using regex

Question

I tried to capture the second match from given text i.e,

hash=e1467eb30743fb0a180ed141a26c58f7&token=a62ef9cf-2b4e-4a99-9335-267b6224b991:IO:OPCA:117804471:OPI:false:en:opsdr:117804471&providerId=paytm

In the above text, I want to capture the second number with the length of 9 (117804471).

I tried following, but it didn't work; so please help me resolving in this.

https://regex101.com/r/vBJceR/1

Answer 1

You can use

^(?:.*?\K\b[0-9]{9}\b){2}

See the regex demo.

Details:

• ^ - start of string
• (?: - start of a non-capturing group:
  • .*? - any zero or more chars other than line break chars (as few as possible) followed with
  • \K - match reset operator discarding text matched so far
  • \b[0-9]{9}\b - a 9-digit number as a whole word
• ){2} - two occurrences of the pattern sequence defined above.