I got json like {"name":"susan","age":25},and a hint to json keyset like "name:String,age:Int",how to create a HList from that json?
How to convert JSON to scala shapeless.hlist?
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Based on the code you added and then deleted, it seems, having a runtime-string hint
"name:String,age:Int"
and runtime-string json{"name":"susan","age":25}
, you want to get anHList
with runtime reflection. You can do this as followsPlease notice that you do everything at runtime so you'll have no access to type
String :: Int :: HNil
at compile time andhlist
has static type justHList
(notString :: Int :: HNil
) andHList
is actually not better than justList[Any]
.build.sbt
Actually, I guess we do someting strange. We use highly type-level libraries (shapeless, circe) aimed to static type safety and then run them at runtime with reflection ignoring type safety and getting actually
List[Any]
(HList
).I guess that if
List[Any]
(list of field values) is enough for you then you just need to use a more runtime library. For example, with json4sbuild.sbt
Actually the same can be done with Circe, just with
parse
instead ofdecode[A]
If you need an instance of case class or a tuple rather than
HList
replacewith
or
correspondingly.