I am developing a React application with jest and TypeMoq.
I can't test the negative path of a decision tree when the mocked call is a method on the object which needs to be undefined. Is there a method on TypeMoq that can help me verify that the provided method is not called?
type TopicComponentProps = {
topic: Topic
history?: History<any>
}
export const TopicComponent = ({topic, history} : TopicComponentProps) => {
const { Id, Name } = topic;
const filterTopic = () => {
if (history) { // <-- this is my problem
history.push(`/topic/overview/${Id}`);
}
}
return(
<Fragment>
<span
style={topicStyle}
onClick={() => filterTopic()}
className="topic">
{Name}
</span>
</Fragment>
)
}
The positive test case looks like this:
it('should trigger the navigation when clicked', () => {
const mockHistory = Mock.ofType<History<any>>();
const wrapper = mount(
<TopicComponent topic={testTopic} history={mockHistory.object} />
);
wrapper.simulate('click');
mockHistory.verify(x => x.push(It.isAnyString()), Times.once());
});
How do I setup the mock object, so i can test that no navigation happens when no history is provided?
it('should not trigger the navigation when history is undefined', () => {
let mockHistory = Mock.ofType<History<any>>();
???
const wrapper = mount(
<TopicComponent topic={testTopic} history={???} />
);
wrapper.simulate('click');
mockHistory.verify(x => x.push(It.isAnyString()), Times.never());
});