I'm using imageio.imread, the folder has 22 tif files the shape of the matrix I get is (514 1030 4), I expect (514 1030 22)

Question

(First time user)

I want to read tif files from a folder.

N=22 (the number of tif files in the folder)

The name of the folder is: tif_files

The file names start at E_0 and ends at E_21

I'm reading the folder using:

for i in range(N):
 im = imageio.imread(path + tifFiles[i])

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I get N from:

N = len(tifFiles)

which gives me 22

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I get tifFiles using:

tifFiles = sorted([f for f in listdir(path) if isfile(join(path, f))])

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The path is: '/Users/name/rsm/tif_files/'

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print(im.shape) gives me (514, 1030, 4) {I'm expecting it to be (514 1030 22)}

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If I print the output list of the files (tifFiles) it gives me the 22 files:

print(tifFiles)

['E_0.tif', 'E_1.tif', 'E_10.tif', 'E_11.tif', 'E_12.tif', 'E_13.tif', 'E_14.tif', 'E_15.tif', 'E_16.tif', 'E_17.tif', 'E_18.tif', 'E_19.tif', 'E_2.tif', 'E_20.tif', 'E_21.tif', 'E_3.tif', 'E_4.tif', 'E_5.tif', 'E_6.tif', 'E_7.tif', 'E_8.tif', 'E_9.tif']

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I put all of this in a function:

function(path,filename)

note: filename is used further downstream in the function to describe the output files of the images

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1. I made sure that I'm in the right path (not reading from somewhere else).
2. I tried using tiff files instead of tif files.
3. I changed the files names from "E_0" to "E0" to discard the use of the underscore

So I have to get 22 arrays of (514 1030) pixels but I'm getting only 4.