In this code you have a code for the door and a keypad for it

Question

I have a door and there's a keypad code for it. If you get the code right you say Correct, if you get it wrong it just prints the wrong code (Just for debugging). However, I don't understand why nothing's happening when I code it. This is python btw:

realnumber = [12345]
inputnumber = []

def main():
  integer = input("Input a list of numbers to open the door:")

  if integer == realnumber:
    print(realnumber)
    print("Correct")
  else:
    inputnumber.append(integer)
main()

Answer 1

This is largely guess work but two issues stand out to me here:

integer = input("Input a list of numbers to open the door:")

You may not be a aware that the variable named integer here is going to a string regardless of your input. Might I suggest you try:

integer = int(input("Input a list of numbers to open the door:"))

or even better, something like this to catch nonsense input:

try:
    integer = int(input("Input a list of numbers to open the door:"))
except ValueError:
    print("Invalid Input")

Secondly,

  if integer == realnumber:

Here you are trying to compare the variable "integer" (which is currently a string but with my suggested change will be an "int" variable) with realnumber, but realnumber is a list of variables that has only one input.

I suggest you choose one of these changes:

  if integer == realnumber[0]:

or

realnumber = 12345