I'm new to SQL, currently I'm doing a task about join two datasets, one of the dataset was created by myself, here's the query I used:
USE `abcde`;
CREATE TABLE `test_01`(
`ID` varchar(50) CHARACTER SET latin1 COLLATE latin1_bin DEFAULT NULL,
`NUMBER01` bigint(20) NOT NULL DEFAULT '0',
`NUMBER02` bigint(20) NOT NULL,
`date01` date DEFAULT NULL,
PRIMARY KEY (`ID`, `date01`))
Then I load the data from a csv file to this table, the csv file looks like this:
ID NUMBER01 NUMBER02 DATE01
aaa=ee 12345678 235896578 **2009-01-01T00:00:00**
If I query this newly-created table, it looks like this(the format of the 'DATE01' changes):
ID NUMBER01 NUMBER02 DATE01
aaa=ee 12345678 235896578 **2009-01-01**
Another dataset, I queried and exported to a csv file, the format of the date01 column is like 01/12/1979 and in SQL the format looks like 1979-12-01.
I also usedselect * from information_schema.columns to check the datatype of the columns I need to join, for the newly-created dataset:

The date column for another dataset is:
The differences are:
1. The format of the date column in csv appears different
2. The COLUMN_DEFAULT are different, one is 0000-00-00, another one is NULL.
I wonder the reason why I got empty output is probably because the difference in the 'date' format, but I'm not sure how to make them the same so that I can get something in the output, can someone gave me some hint? Thank you.
Of course, DATE datatype does not contain timezone info/component.
If input value have some disadvantage (like wrong data format) than according value is truncated or is set to NULL. See - you must obtain a bunch of warnings during the importing similar to "truncate incorrect value".
If the date field in CSV have wrong format then you must use intermediate user-defined variable for accepting raw value, and apply proper converting expression to it in SET clause. Like