I have the following GraphQL schema, which defines 3 types: a CondaPackage which hasmany CondaVersion, which hasmany CondaExecutable. I want to be able to query a CondaVersion and ask "how many CondaExecutables do you own which succeeded my analysis". Currently I've written a succeededExeCount and allExeCount which resolve this field by loading all children and manually counting the number of children that succeeded.
exports.createSchemaCustomization = ({ actions: { createTypes }, schema }) => {
createTypes([
schema.buildObjectType({
name: "CondaPackage",
fields: {
succeededExeCount: {
type: "Int!",
resolve(source, args, context){
// TODO
}
},
allExeCount: {
type: "Int!",
resolve(source, args, context){
// TODO
}
}
},
interfaces: ["Node"]
}),
schema.buildObjectType({
name: "CondaVersion",
fields: {
succeededExeCount: {
type: "Float!",
resolve(source, args, context){
const children = context.nodeModel.getNodesByIds({
ids: source.children,
type: "CondaExecutable"
})
return children.reduce((acc, curr) => acc + curr.fields.succeeded, 0)
}
},
allExeCount: {
type: "Int!",
resolve(source, args, context){
return source.children.length;
}
}
},
interfaces: ["Node"]
}),
schema.buildObjectType({
name: "CondaExecutable",
fields: {
succeeded: {
type: "Boolean!",
resolve(source, args, context, info) {
return source.fields.succeeded || false;
}
},
},
interfaces: ["Node"]
})
])
}
My first problem is that this seems incredibly inefficient. For each CondaVersion I'm running a separate query for its children, which is a classic N+1 query problem. Is there a way to tell Gatsby/GraphQL to simply "join" the two tables like I would using SQL to avoid this?
My second problem is that I now need to count the number of succeeding children from the top level type: CondaPackage. I want to ask "how many CondaExecutables do your child CondaVersions own which succeeded my analysis". Again, in SQL this would be easy because I would just JOIN the 3 types. However, the only way I can currently do this is by using getNodesByIds for each child, and then for each child's child, which is n*m*o runtime, which is terrifying. I would like to run a GraphQL query as part of the field resolution which lets me grab the succeededExeCount from each child. However, Gatsby's runQuery seems to return nodes without including derived fields, and it won't let me select additional fields to return. How can I access fields on a node's child's child in Gatsby?
Edit
Here's the response from a Gatsby maintainer regarding the workaround:
See the full thread here.
Original Answer
Here's a little 'secret' (not mentioned anywhere in the docs at the time of writing):
When you use
runQuery, Gatsby will try to resolve derived fields... but only if that field is passed to the query's options (filter, sort, group, distinct).For example, in
CondaVersion, instead of accessing children nodes and look upfields.succeeded, you can do this:Same thing for
CondaPackage. You might try to do thisYou'll probably find that
succeededExeCountisundefined.The trick is to do this:
It's counter intuitive, because you'd think Gatsby would just resolve all resolvable fields on a type. Instead it only resolves fields that is 'used'. So to get around this, we add a filter that supposedly does nothing.
But that's not all yet,
node.succeededExeCountis stillundefined.The resolved data (
succeededExeCount) is not directly stored on the node itself, but innode.__gatsby_resolvedsource. We'll have to access it there instead.Give it a try & let me know if that works.
PS: I notice that you probably use
createNodeField(inCondaExec'snode.fields.succeeded?)createTypesis also accessible inexports.sourceNodes, so you might be able to add thissucceededfield directly.