In this image it says the Output should be A' + B, but to me, it seems like it should be A' + AB. If I'm wrong, could someone explain to me how A' + B is the correct answer? The reason I ask this is because in the second group of ones, you get ABC + ABC'. Since A and B areboth common in the last two groups, shouldn't they both be included? Thanks in advance.
Simplifying a Karnaugh Map
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The key bit you are missing is that
A' + Bis equal toA' + ABBecause of the Distributive Property of boolean algebra we can rewrite
as the product
and since the first term is the same as just saying
1, we are left with only our second term.