The answers on this question state that long commands can be split into multiple lines via the use of the caret character (^). One answer provides a technical description:
the caret and the newline that follows it are removed entirely from the command
However, this doesn't always seem to work when piping commands and using the piping symbol (|).
Take a look at the following examples:
Code to split:
dir | sort
❌ DOES NOT WORK
dir ^
| sort
✅ WORKS #1
dir ^
| sort
Notice the space in 2nd line
✅ WORKS #2
dir |^
sort
Would love to know why this is the case :)
As this answer states, somewhat cryptically, the full technical definition of how the caret (
^) works is as follows:A caret at the end of the line:
^) you typedSince the piping symbol
|is the first character in the next line, it will be escaped and thus lose its special meaning and just be interpreted as a text character.Examples:
Turns into:
The
^character is the escape character. The forward slash/carries no special meaning, so escaping it has no effect, making the command work as expected and effectively turning it into this:However, look at this:
Turns into:
Which escapes the special
&character (which has the special meaning of executing the right command after the left one). You will get an error since all of& echo hellowill be sent as parameters to thedircommand.Which means that something like this will work:
Turns into:
The first
&is escaped, while the second&is interpreted correctly. This will rundir ^&, which sends&(raw text character) as the directory parameter fordir, and then runecho hellobecause of the second&character working as normal.dir ^&will fail because "&" is no valid directory, and thenecho hellowill print out "hello".Returning to piping, let's look at the example you provided that's not working:
Turns into:
The piping symbol
|will be escaped and not be interpreted as piping (it will appear as text character). And thus, "| sort" will be sent as parameters to thedircommand, which won't find the directory, and fail.To solve this, as you already figured out, you need to add a space at the start of the next line.
This way, the space will be escaped, while the subsequent pipe symbol
|will be interpreted as normal:Turns into:
Which is effectively: