I try to calculate the arctan(a/b) by calculating arccot(b/a) for small b and larger a to increase numerical stability of my calculations but numpy seems not to provide an arccot function?
Edit: Ok @hpaulj pointed out there is an arctan2 / tan2 function. I looked it up and it basically removes the numerical stability problems by not dividing at all but taking the numerator and denominator as separate inputs.