Consider:
164b: f3 0f 1e fa endbr64
164f: 55 push %rbp
1650: 53 push %rbx
1651: 48 83 ec 28 sub $0x28,%rsp
1655: 64 48 8b 04 25 28 00 mov %fs:0x28,%rax
165c: 00 00
165e: 48 89 44 24 18 mov %rax,0x18(%rsp)
1663: 31 c0 xor %eax,%eax
1665: 48 89 e6 mov %rsp,%rsi
1668: e8 18 08 00 00 call 1e85 <read_six_numbers>
166d: 83 3c 24 01 cmpl $0x1,(%rsp)
1671: 75 0a jne 167d <phase_2+0x32>
1673: 48 89 e5 mov %rsp,%rbp
1676: bb 02 00 00 00 mov $0x2,%ebx
167b: eb 13 jmp 1690 <phase_2+0x45>
167d: e8 c1 07 00 00 call 1e43 <explode_bomb>
1682: eb ef jmp 1673 <phase_2+0x28>
1684: 83 c3 01 add $0x1,%ebx
1687: 48 83 c5 04 add $0x4,%rbp
168b: 83 fb 07 cmp $0x7,%ebx
168e: 74 12 je 16a2 <phase_2+0x57>
1690: 89 d8 mov %ebx,%eax
1692: 0f af 45 00 imul 0x0(%rbp),%eax
1696: 39 45 04 cmp %eax,0x4(%rbp)
1699: 74 e9 je 1684 <phase_2+0x39>
169b: e8 a3 07 00 00 call 1e43 <explode_bomb>
16a0: eb e2 jmp 1684 <phase_2+0x39>
16a2: 48 8b 44 24 18 mov 0x18(%rsp),%rax
16a7: 64 48 2b 04 25 28 00 sub %fs:0x28,%rax
16ae: 00 00
16b0: 75 07 jne 16b9 <phase_2+0x6e>
16b2: 48 83 c4 28 add $0x28,%rsp
16b6: 5b pop %rbx
16b7: 5d pop %rbp
16b8: c3 ret
16b9: e8 c2 fb ff ff call 1280 <__stack_chk_fail@plt>
Given the code above, I speculated that %rbp would be equal to a decimal value of -40, but I know this is incorrect, and I don’t know enough about assembly to figure out where my logic went wrong.
I’m not entirely sure what the output is supposed to be, but I am not sure if the answer I came up with makes sense, because line 1696 compares if %eax is equal to %rbp + 4, but if %rbp is -40, this statement will never execute, resulting in an infinite loop.