Adding Long option to the script

Question

Consider I have a curl command:

'curl' '--noproxy' 'check' '-H' 'Authorization: token ${TOKEN}' '-H', 'Accept: application/vnd.github.v3+json' '--create-dirs' '-o' successFile.toString()  "Url"

Below script is to test the working of curl command and Here I want to add long option --noproxy to the below script:

#!/bin/sh

string_matches() {
    eval "
    case \$1 in
        $2) return 0 ;;
        *) return 1 ;;
    esac
    "
}

FULL_COMMAND="$@"
while getopts "H:o:H:X:d:-:" OPT; do
    if [ "$OPT" = "-" ]; then # long option: reformulate OPT and OPTARG
        OPT="${OPTARG%%=*}"    
        OPTARG="${OPTARG#$OPT}" 
        OPTARG="${OPTARG#=}"  
    fi
    case "${OPT}" in
      o) OUTPUT_FILE="${OPTARG}" ;;
      create-dirs) CREATE_DIRS=1 ;;
    ?) ;;
    esac
done

shift $(($OPTIND - 1))
CURL_URL=$1

if [ -n "${CREATE_DIRS:-}" ]; then
    mkdir -p $(dirname ${OUTPUT_FILE})
fi

if string_matches "${CURL_URL}" '*content.properties*'; then
    echo 'success' >"${OUTPUT_FILE}"
else
    exit 97 #WAT
fi

I tried adding noproxy in case

case "${OPT}" in
n|noproxy) NOPROXY='check';;

but it doesn't seem to work, but if I remove the noproxy option, everything else is working perfectly. Tried using this answer but no luck https://stackoverflow.com/a/28466267/21758758